| /* |
| Red Black Trees |
| (C) 1999 Andrea Arcangeli <andrea@suse.de> |
| (C) 2002 David Woodhouse <dwmw2@infradead.org> |
| |
| This program is free software; you can redistribute it and/or modify |
| it under the terms of the GNU General Public License as published by |
| the Free Software Foundation; either version 2 of the License, or |
| (at your option) any later version. |
| |
| This program is distributed in the hope that it will be useful, |
| but WITHOUT ANY WARRANTY; without even the implied warranty of |
| MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the |
| GNU General Public License for more details. |
| |
| You should have received a copy of the GNU General Public License |
| along with this program; if not, write to the Free Software |
| Foundation, Inc., 59 Temple Place, Suite 330, Boston, MA 02111-1307 USA |
| |
| linux/lib/rbtree.c |
| */ |
| |
| #include <linux/rbtree.h> |
| #include <linux/export.h> |
| |
| /* |
| * red-black trees properties: http://en.wikipedia.org/wiki/Rbtree |
| * |
| * 1) A node is either red or black |
| * 2) The root is black |
| * 3) All leaves (NULL) are black |
| * 4) Both children of every red node are black |
| * 5) Every simple path from root to leaves contains the same number |
| * of black nodes. |
| * |
| * 4 and 5 give the O(log n) guarantee, since 4 implies you cannot have two |
| * consecutive red nodes in a path and every red node is therefore followed by |
| * a black. So if B is the number of black nodes on every simple path (as per |
| * 5), then the longest possible path due to 4 is 2B. |
| * |
| * We shall indicate color with case, where black nodes are uppercase and red |
| * nodes will be lowercase. Unknown color nodes shall be drawn as red within |
| * parentheses and have some accompanying text comment. |
| */ |
| |
| #define RB_RED 0 |
| #define RB_BLACK 1 |
| |
| #define rb_color(r) ((r)->__rb_parent_color & 1) |
| #define rb_is_red(r) (!rb_color(r)) |
| #define rb_is_black(r) rb_color(r) |
| |
| static inline void rb_set_parent(struct rb_node *rb, struct rb_node *p) |
| { |
| rb->__rb_parent_color = rb_color(rb) | (unsigned long)p; |
| } |
| |
| static inline void rb_set_parent_color(struct rb_node *rb, |
| struct rb_node *p, int color) |
| { |
| rb->__rb_parent_color = (unsigned long)p | color; |
| } |
| |
| static inline struct rb_node *rb_red_parent(struct rb_node *red) |
| { |
| return (struct rb_node *)red->__rb_parent_color; |
| } |
| |
| /* |
| * Helper function for rotations: |
| * - old's parent and color get assigned to new |
| * - old gets assigned new as a parent and 'color' as a color. |
| */ |
| static inline void |
| __rb_rotate_set_parents(struct rb_node *old, struct rb_node *new, |
| struct rb_root *root, int color) |
| { |
| struct rb_node *parent = rb_parent(old); |
| new->__rb_parent_color = old->__rb_parent_color; |
| rb_set_parent_color(old, new, color); |
| if (parent) { |
| if (parent->rb_left == old) |
| parent->rb_left = new; |
| else |
| parent->rb_right = new; |
| } else |
| root->rb_node = new; |
| } |
| |
| void rb_insert_color(struct rb_node *node, struct rb_root *root) |
| { |
| struct rb_node *parent = rb_red_parent(node), *gparent, *tmp; |
| |
| while (true) { |
| /* |
| * Loop invariant: node is red |
| * |
| * If there is a black parent, we are done. |
| * Otherwise, take some corrective action as we don't |
| * want a red root or two consecutive red nodes. |
| */ |
| if (!parent) { |
| rb_set_parent_color(node, NULL, RB_BLACK); |
| break; |
| } else if (rb_is_black(parent)) |
| break; |
| |
| gparent = rb_red_parent(parent); |
| |
| if (parent == gparent->rb_left) { |
| tmp = gparent->rb_right; |
| if (tmp && rb_is_red(tmp)) { |
| /* |
| * Case 1 - color flips |
| * |
| * G g |
| * / \ / \ |
| * p u --> P U |
| * / / |
| * n N |
| * |
| * However, since g's parent might be red, and |
| * 4) does not allow this, we need to recurse |
| * at g. |
| */ |
| rb_set_parent_color(tmp, gparent, RB_BLACK); |
| rb_set_parent_color(parent, gparent, RB_BLACK); |
| node = gparent; |
| parent = rb_parent(node); |
| rb_set_parent_color(node, parent, RB_RED); |
| continue; |
| } |
| |
| if (parent->rb_right == node) { |
| /* |
| * Case 2 - left rotate at parent |
| * |
| * G G |
| * / \ / \ |
| * p U --> n U |
| * \ / |
| * n p |
| * |
| * This still leaves us in violation of 4), the |
| * continuation into Case 3 will fix that. |
| */ |
| parent->rb_right = tmp = node->rb_left; |
| node->rb_left = parent; |
| if (tmp) |
| rb_set_parent_color(tmp, parent, |
| RB_BLACK); |
| rb_set_parent_color(parent, node, RB_RED); |
| parent = node; |
| } |
| |
| /* |
| * Case 3 - right rotate at gparent |
| * |
| * G P |
| * / \ / \ |
| * p U --> n g |
| * / \ |
| * n U |
| */ |
| gparent->rb_left = tmp = parent->rb_right; |
| parent->rb_right = gparent; |
| if (tmp) |
| rb_set_parent_color(tmp, gparent, RB_BLACK); |
| __rb_rotate_set_parents(gparent, parent, root, RB_RED); |
| break; |
| } else { |
| tmp = gparent->rb_left; |
| if (tmp && rb_is_red(tmp)) { |
| /* Case 1 - color flips */ |
| rb_set_parent_color(tmp, gparent, RB_BLACK); |
| rb_set_parent_color(parent, gparent, RB_BLACK); |
| node = gparent; |
| parent = rb_parent(node); |
| rb_set_parent_color(node, parent, RB_RED); |
| continue; |
| } |
| |
| if (parent->rb_left == node) { |
| /* Case 2 - right rotate at parent */ |
| parent->rb_left = tmp = node->rb_right; |
| node->rb_right = parent; |
| if (tmp) |
| rb_set_parent_color(tmp, parent, |
| RB_BLACK); |
| rb_set_parent_color(parent, node, RB_RED); |
| parent = node; |
| } |
| |
| /* Case 3 - left rotate at gparent */ |
| gparent->rb_right = tmp = parent->rb_left; |
| parent->rb_left = gparent; |
| if (tmp) |
| rb_set_parent_color(tmp, gparent, RB_BLACK); |
| __rb_rotate_set_parents(gparent, parent, root, RB_RED); |
| break; |
| } |
| } |
| } |
| EXPORT_SYMBOL(rb_insert_color); |
| |
| static void __rb_erase_color(struct rb_node *node, struct rb_node *parent, |
| struct rb_root *root) |
| { |
| struct rb_node *sibling, *tmp1, *tmp2; |
| |
| while (true) { |
| /* |
| * Loop invariant: all leaf paths going through node have a |
| * black node count that is 1 lower than other leaf paths. |
| * |
| * If node is red, we can flip it to black to adjust. |
| * If node is the root, all leaf paths go through it. |
| * Otherwise, we need to adjust the tree through color flips |
| * and tree rotations as per one of the 4 cases below. |
| */ |
| if (node && rb_is_red(node)) { |
| rb_set_parent_color(node, parent, RB_BLACK); |
| break; |
| } else if (!parent) { |
| break; |
| } else if (parent->rb_left == node) { |
| sibling = parent->rb_right; |
| if (rb_is_red(sibling)) { |
| /* |
| * Case 1 - left rotate at parent |
| * |
| * P S |
| * / \ / \ |
| * N s --> p Sr |
| * / \ / \ |
| * Sl Sr N Sl |
| */ |
| parent->rb_right = tmp1 = sibling->rb_left; |
| sibling->rb_left = parent; |
| rb_set_parent_color(tmp1, parent, RB_BLACK); |
| __rb_rotate_set_parents(parent, sibling, root, |
| RB_RED); |
| sibling = tmp1; |
| } |
| tmp1 = sibling->rb_right; |
| if (!tmp1 || rb_is_black(tmp1)) { |
| tmp2 = sibling->rb_left; |
| if (!tmp2 || rb_is_black(tmp2)) { |
| /* |
| * Case 2 - sibling color flip |
| * (p could be either color here) |
| * |
| * (p) (p) |
| * / \ / \ |
| * N S --> N s |
| * / \ / \ |
| * Sl Sr Sl Sr |
| * |
| * This leaves us violating 5), so |
| * recurse at p. If p is red, the |
| * recursion will just flip it to black |
| * and exit. If coming from Case 1, |
| * p is known to be red. |
| */ |
| rb_set_parent_color(sibling, parent, |
| RB_RED); |
| node = parent; |
| parent = rb_parent(node); |
| continue; |
| } |
| /* |
| * Case 3 - right rotate at sibling |
| * (p could be either color here) |
| * |
| * (p) (p) |
| * / \ / \ |
| * N S --> N Sl |
| * / \ \ |
| * sl Sr s |
| * \ |
| * Sr |
| */ |
| sibling->rb_left = tmp1 = tmp2->rb_right; |
| tmp2->rb_right = sibling; |
| parent->rb_right = tmp2; |
| if (tmp1) |
| rb_set_parent_color(tmp1, sibling, |
| RB_BLACK); |
| tmp1 = sibling; |
| sibling = tmp2; |
| } |
| /* |
| * Case 4 - left rotate at parent + color flips |
| * (p and sl could be either color here. |
| * After rotation, p becomes black, s acquires |
| * p's color, and sl keeps its color) |
| * |
| * (p) (s) |
| * / \ / \ |
| * N S --> P Sr |
| * / \ / \ |
| * (sl) sr N (sl) |
| */ |
| parent->rb_right = tmp2 = sibling->rb_left; |
| sibling->rb_left = parent; |
| rb_set_parent_color(tmp1, sibling, RB_BLACK); |
| if (tmp2) |
| rb_set_parent(tmp2, parent); |
| __rb_rotate_set_parents(parent, sibling, root, |
| RB_BLACK); |
| break; |
| } else { |
| sibling = parent->rb_left; |
| if (rb_is_red(sibling)) { |
| /* Case 1 - right rotate at parent */ |
| parent->rb_left = tmp1 = sibling->rb_right; |
| sibling->rb_right = parent; |
| rb_set_parent_color(tmp1, parent, RB_BLACK); |
| __rb_rotate_set_parents(parent, sibling, root, |
| RB_RED); |
| sibling = tmp1; |
| } |
| tmp1 = sibling->rb_left; |
| if (!tmp1 || rb_is_black(tmp1)) { |
| tmp2 = sibling->rb_right; |
| if (!tmp2 || rb_is_black(tmp2)) { |
| /* Case 2 - sibling color flip */ |
| rb_set_parent_color(sibling, parent, |
| RB_RED); |
| node = parent; |
| parent = rb_parent(node); |
| continue; |
| } |
| /* Case 3 - right rotate at sibling */ |
| sibling->rb_right = tmp1 = tmp2->rb_left; |
| tmp2->rb_left = sibling; |
| parent->rb_left = tmp2; |
| if (tmp1) |
| rb_set_parent_color(tmp1, sibling, |
| RB_BLACK); |
| tmp1 = sibling; |
| sibling = tmp2; |
| } |
| /* Case 4 - left rotate at parent + color flips */ |
| parent->rb_left = tmp2 = sibling->rb_right; |
| sibling->rb_right = parent; |
| rb_set_parent_color(tmp1, sibling, RB_BLACK); |
| if (tmp2) |
| rb_set_parent(tmp2, parent); |
| __rb_rotate_set_parents(parent, sibling, root, |
| RB_BLACK); |
| break; |
| } |
| } |
| } |
| |
| void rb_erase(struct rb_node *node, struct rb_root *root) |
| { |
| struct rb_node *child, *parent; |
| int color; |
| |
| if (!node->rb_left) |
| child = node->rb_right; |
| else if (!node->rb_right) |
| child = node->rb_left; |
| else |
| { |
| struct rb_node *old = node, *left; |
| |
| node = node->rb_right; |
| while ((left = node->rb_left) != NULL) |
| node = left; |
| |
| if (rb_parent(old)) { |
| if (rb_parent(old)->rb_left == old) |
| rb_parent(old)->rb_left = node; |
| else |
| rb_parent(old)->rb_right = node; |
| } else |
| root->rb_node = node; |
| |
| child = node->rb_right; |
| parent = rb_parent(node); |
| color = rb_color(node); |
| |
| if (parent == old) { |
| parent = node; |
| } else { |
| if (child) |
| rb_set_parent(child, parent); |
| parent->rb_left = child; |
| |
| node->rb_right = old->rb_right; |
| rb_set_parent(old->rb_right, node); |
| } |
| |
| node->__rb_parent_color = old->__rb_parent_color; |
| node->rb_left = old->rb_left; |
| rb_set_parent(old->rb_left, node); |
| |
| goto color; |
| } |
| |
| parent = rb_parent(node); |
| color = rb_color(node); |
| |
| if (child) |
| rb_set_parent(child, parent); |
| if (parent) |
| { |
| if (parent->rb_left == node) |
| parent->rb_left = child; |
| else |
| parent->rb_right = child; |
| } |
| else |
| root->rb_node = child; |
| |
| color: |
| if (color == RB_BLACK) |
| __rb_erase_color(child, parent, root); |
| } |
| EXPORT_SYMBOL(rb_erase); |
| |
| static void rb_augment_path(struct rb_node *node, rb_augment_f func, void *data) |
| { |
| struct rb_node *parent; |
| |
| up: |
| func(node, data); |
| parent = rb_parent(node); |
| if (!parent) |
| return; |
| |
| if (node == parent->rb_left && parent->rb_right) |
| func(parent->rb_right, data); |
| else if (parent->rb_left) |
| func(parent->rb_left, data); |
| |
| node = parent; |
| goto up; |
| } |
| |
| /* |
| * after inserting @node into the tree, update the tree to account for |
| * both the new entry and any damage done by rebalance |
| */ |
| void rb_augment_insert(struct rb_node *node, rb_augment_f func, void *data) |
| { |
| if (node->rb_left) |
| node = node->rb_left; |
| else if (node->rb_right) |
| node = node->rb_right; |
| |
| rb_augment_path(node, func, data); |
| } |
| EXPORT_SYMBOL(rb_augment_insert); |
| |
| /* |
| * before removing the node, find the deepest node on the rebalance path |
| * that will still be there after @node gets removed |
| */ |
| struct rb_node *rb_augment_erase_begin(struct rb_node *node) |
| { |
| struct rb_node *deepest; |
| |
| if (!node->rb_right && !node->rb_left) |
| deepest = rb_parent(node); |
| else if (!node->rb_right) |
| deepest = node->rb_left; |
| else if (!node->rb_left) |
| deepest = node->rb_right; |
| else { |
| deepest = rb_next(node); |
| if (deepest->rb_right) |
| deepest = deepest->rb_right; |
| else if (rb_parent(deepest) != node) |
| deepest = rb_parent(deepest); |
| } |
| |
| return deepest; |
| } |
| EXPORT_SYMBOL(rb_augment_erase_begin); |
| |
| /* |
| * after removal, update the tree to account for the removed entry |
| * and any rebalance damage. |
| */ |
| void rb_augment_erase_end(struct rb_node *node, rb_augment_f func, void *data) |
| { |
| if (node) |
| rb_augment_path(node, func, data); |
| } |
| EXPORT_SYMBOL(rb_augment_erase_end); |
| |
| /* |
| * This function returns the first node (in sort order) of the tree. |
| */ |
| struct rb_node *rb_first(const struct rb_root *root) |
| { |
| struct rb_node *n; |
| |
| n = root->rb_node; |
| if (!n) |
| return NULL; |
| while (n->rb_left) |
| n = n->rb_left; |
| return n; |
| } |
| EXPORT_SYMBOL(rb_first); |
| |
| struct rb_node *rb_last(const struct rb_root *root) |
| { |
| struct rb_node *n; |
| |
| n = root->rb_node; |
| if (!n) |
| return NULL; |
| while (n->rb_right) |
| n = n->rb_right; |
| return n; |
| } |
| EXPORT_SYMBOL(rb_last); |
| |
| struct rb_node *rb_next(const struct rb_node *node) |
| { |
| struct rb_node *parent; |
| |
| if (RB_EMPTY_NODE(node)) |
| return NULL; |
| |
| /* If we have a right-hand child, go down and then left as far |
| as we can. */ |
| if (node->rb_right) { |
| node = node->rb_right; |
| while (node->rb_left) |
| node=node->rb_left; |
| return (struct rb_node *)node; |
| } |
| |
| /* No right-hand children. Everything down and left is |
| smaller than us, so any 'next' node must be in the general |
| direction of our parent. Go up the tree; any time the |
| ancestor is a right-hand child of its parent, keep going |
| up. First time it's a left-hand child of its parent, said |
| parent is our 'next' node. */ |
| while ((parent = rb_parent(node)) && node == parent->rb_right) |
| node = parent; |
| |
| return parent; |
| } |
| EXPORT_SYMBOL(rb_next); |
| |
| struct rb_node *rb_prev(const struct rb_node *node) |
| { |
| struct rb_node *parent; |
| |
| if (RB_EMPTY_NODE(node)) |
| return NULL; |
| |
| /* If we have a left-hand child, go down and then right as far |
| as we can. */ |
| if (node->rb_left) { |
| node = node->rb_left; |
| while (node->rb_right) |
| node=node->rb_right; |
| return (struct rb_node *)node; |
| } |
| |
| /* No left-hand children. Go up till we find an ancestor which |
| is a right-hand child of its parent */ |
| while ((parent = rb_parent(node)) && node == parent->rb_left) |
| node = parent; |
| |
| return parent; |
| } |
| EXPORT_SYMBOL(rb_prev); |
| |
| void rb_replace_node(struct rb_node *victim, struct rb_node *new, |
| struct rb_root *root) |
| { |
| struct rb_node *parent = rb_parent(victim); |
| |
| /* Set the surrounding nodes to point to the replacement */ |
| if (parent) { |
| if (victim == parent->rb_left) |
| parent->rb_left = new; |
| else |
| parent->rb_right = new; |
| } else { |
| root->rb_node = new; |
| } |
| if (victim->rb_left) |
| rb_set_parent(victim->rb_left, new); |
| if (victim->rb_right) |
| rb_set_parent(victim->rb_right, new); |
| |
| /* Copy the pointers/colour from the victim to the replacement */ |
| *new = *victim; |
| } |
| EXPORT_SYMBOL(rb_replace_node); |