[TCP]: Unite identical code from two seqno split blocks
Bogus seqno compares just mislead, the code is identical for
both sides of the seqno compare (and was even executed just
once because of return in between).
Signed-off-by: Ilpo Järvinen <ilpo.jarvinen@helsinki.fi>
Signed-off-by: Herbert Xu <herbert@gondor.apana.org.au>
Signed-off-by: David S. Miller <davem@davemloft.net>
diff --git a/net/ipv4/tcp_input.c b/net/ipv4/tcp_input.c
index 8711108..d313dea 100644
--- a/net/ipv4/tcp_input.c
+++ b/net/ipv4/tcp_input.c
@@ -1246,8 +1246,7 @@
if (dup_sack && (sacked & TCPCB_RETRANS)) {
if (after(TCP_SKB_CB(skb)->end_seq, tp->undo_marker))
tp->undo_retrans--;
- if (!after(TCP_SKB_CB(skb)->end_seq, tp->snd_una) &&
- (sacked & TCPCB_SACKED_ACKED))
+ if (sacked & TCPCB_SACKED_ACKED)
*reord = min(fack_count, *reord);
}
@@ -1310,10 +1309,6 @@
if (after(TCP_SKB_CB(skb)->seq, tcp_highest_sack_seq(tp)))
tp->highest_sack = skb;
-
- } else {
- if (dup_sack && (sacked & TCPCB_RETRANS))
- *reord = min(fack_count, *reord);
}
/* D-SACK. We can detect redundant retransmission in S|R and plain R