rxrpc: Provide a way for AFS to ask for the peer address of a call
Provide a function so that kernel users, such as AFS, can ask for the peer
address of a call:
void rxrpc_kernel_get_peer(struct rxrpc_call *call,
struct sockaddr_rxrpc *_srx);
In the future the kernel service won't get sk_buffs to look inside.
Further, this allows us to hide any canonicalisation inside AF_RXRPC for
when IPv6 support is added.
Also propagate this through to afs_find_server() and issue a warning if we
can't handle the address family yet.
Signed-off-by: David Howells <dhowells@redhat.com>
diff --git a/fs/afs/server.c b/fs/afs/server.c
index f342acf..d4066ab 100644
--- a/fs/afs/server.c
+++ b/fs/afs/server.c
@@ -178,13 +178,18 @@
/*
* look up a server by its IP address
*/
-struct afs_server *afs_find_server(const struct in_addr *_addr)
+struct afs_server *afs_find_server(const struct sockaddr_rxrpc *srx)
{
struct afs_server *server = NULL;
struct rb_node *p;
- struct in_addr addr = *_addr;
+ struct in_addr addr = srx->transport.sin.sin_addr;
- _enter("%pI4", &addr.s_addr);
+ _enter("{%d,%pI4}", srx->transport.family, &addr.s_addr);
+
+ if (srx->transport.family != AF_INET) {
+ WARN(true, "AFS does not yes support non-IPv4 addresses\n");
+ return NULL;
+ }
read_lock(&afs_servers_lock);